Solve the Inequality for p -18<-2p<=12

$- 18 < - 2 p \leq 12$

Step 1

Divide each term in the inequality by $- 2$ .

$\frac{- 18}{- 2} > \frac{- 2 p}{- 2} \geq \frac{12}{- 2}$

Step 2

Divide $- 18$ by $- 2$ .

$9 > \frac{- 2 p}{- 2} \geq \frac{12}{- 2}$

Step 3

Cancel the common factor of $- 2$ .

Cancel the common factor.

$9 > \frac{- 2 p}{- 2} \geq \frac{12}{- 2}$

Divide $p$ by $1$ .

$9 > p \geq \frac{12}{- 2}$

Step 4

Divide $12$ by $- 2$ .

$9 > p \geq - 6$

Step 5

Rewrite the interval so that the left value is less than the right value. This is the correct way to write an interval solution.

$- 6 \leq p < 9$

Step 6

The result can be shown in multiple forms.

Inequality Form:

$- 6 \leq p < 9$

Interval Notation:

$[- 6, 9)$

Step 7