Solve the Inequality for p 2<=-8+p/2

$2 \leq - 8 + \frac{p}{2}$

Rewrite so $p$ is on the left side of the inequality.

$- 8 + \frac{p}{2} \geq 2$

Move all terms not containing $p$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$\frac{p}{2} \geq 2 + 8$

Add $2$ and $8$ .

$\frac{p}{2} \geq 10$

Multiply both sides by $2$ .

$\frac{p}{2} \cdot 2 \geq 10 \cdot 2$

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{p}{2} \cdot 2 \geq 10 \cdot 2$

Rewrite the expression.

$p \geq 10 \cdot 2$

Simplify the right side.

Multiply $10$ by $2$ .

$p \geq 20$

The result can be shown in multiple forms.

Inequality Form:

$p \geq 20$

Interval Notation:

$[20, \infty)$