Solve the Inequality for p -3(p+1)<=-18

$- 3 (p + 1) \leq - 18$

Divide each term in $- 3 (p + 1) \leq - 18$ by $- 3$ and simplify.

Divide each term in $- 3 (p + 1) \leq - 18$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 (p + 1)}{- 3} \geq \frac{- 18}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (p + 1)}{- 3} \geq \frac{- 18}{- 3}$

Divide $p + 1$ by $1$ .

$p + 1 \geq \frac{- 18}{- 3}$

Simplify the right side.

Divide $- 18$ by $- 3$ .

$p + 1 \geq 6$

Move all terms not containing $p$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$p \geq 6 - 1$

Subtract $1$ from $6$ .

$p \geq 5$

The result can be shown in multiple forms.

Inequality Form:

$p \geq 5$

Interval Notation:

$[5, \infty)$

Solve the Inequality for p -3(p+1)<=-18

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