Solve the Inequality for p 7p-11p+3>=3-4p

$7 p - 11 p + 3 \geq 3 - 4 p$

Subtract $11 p$ from $7 p$ .

$- 4 p + 3 \geq 3 - 4 p$

Move all terms containing $p$ to the left side of the inequality.

Add $4 p$ to both sides of the inequality.

$- 4 p + 3 + 4 p \geq 3$

Combine the opposite terms in $- 4 p + 3 + 4 p$ .

Add $- 4 p$ and $4 p$ .

$0 + 3 \geq 3$

Add $0$ and $3$ .

$3 \geq 3$

Since $3 = 3$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$