Solve the Inequality for p 9(p+2)<=3(3p-5)

$9 (p + 2) \leq 3 (3 p - 5)$

Step 1

Simplify $9 (p + 2)$ .

Start simplifying.

$0 + 0 + 9 (p + 2) \leq 3 (3 p - 5)$

Simplify by adding zeros.

$9 (p + 2) \leq 3 (3 p - 5)$

Apply the distributive property.

$9 p + 9 \cdot 2 \leq 3 (3 p - 5)$

Multiply $9$ by $2$ .

$9 p + 18 \leq 3 (3 p - 5)$

Step 2

Simplify $3 (3 p - 5)$ .

Apply the distributive property.

$9 p + 18 \leq 3 (3 p) + 3 \cdot - 5$

Multiply.

Multiply $3$ by $3$ .

$9 p + 18 \leq 9 p + 3 \cdot - 5$

Multiply $3$ by $- 5$ .

$9 p + 18 \leq 9 p - 15$

Step 3

Move all terms containing $p$ to the left side of the inequality.

Subtract $9 p$ from both sides of the inequality.

$9 p + 18 - 9 p \leq - 15$

Combine the opposite terms in $9 p + 18 - 9 p$ .

Subtract $9 p$ from $9 p$ .

$0 + 18 \leq - 15$

Add $0$ and $18$ .

$18 \leq - 15$

Step 4

Since $18 \neq - 15$ , there are no solutions.

No solution