Solve the Inequality for q -6q-1>=10q-2

$- 6 q - 1 \geq 10 q - 2$

Step 1

Move all terms containing $q$ to the left side of the inequality.

Subtract $10 q$ from both sides of the inequality.

$- 6 q - 1 - 10 q \geq - 2$

Subtract $10 q$ from $- 6 q$ .

$- 16 q - 1 \geq - 2$

Step 2

Move all terms not containing $q$ to the right side of the inequality.

Add $1$ to both sides of the inequality.

$- 16 q \geq - 2 + 1$

Add $- 2$ and $1$ .

$- 16 q \geq - 1$

Step 3

Divide each term in $- 16 q \geq - 1$ by $- 16$ and simplify.

Divide each term in $- 16 q \geq - 1$ by $- 16$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 16 q}{- 16} \leq \frac{- 1}{- 16}$

Simplify the left side.

Cancel the common factor of $- 16$ .

Cancel the common factor.

$\frac{- 16 q}{- 16} \leq \frac{- 1}{- 16}$

Divide $q$ by $1$ .

$q \leq \frac{- 1}{- 16}$

Simplify the right side.

Dividing two negative values results in a positive value.

$q \leq \frac{1}{16}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$q \leq \frac{1}{16}$

Interval Notation:

$(- \infty, \frac{1}{16}]$

Solve the Inequality for q -6q-1>=10q-2

Related Questions

Support LCMGCF.com by disabling your adblocker.