Solve the Inequality for r (-8+r)/2>-8

$\frac{- 8 + r}{2} > - 8$

Multiply both sides by $2$ .

$\frac{- 8 + r}{2} \cdot 2 > - 8 \cdot 2$

Simplify.

Simplify the left side.

Simplify $\frac{- 8 + r}{2} \cdot 2$ .

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{- 8 + r}{2} \cdot 2 > - 8 \cdot 2$

Rewrite the expression.

$- 8 + r > - 8 \cdot 2$

Reorder $- 8$ and $r$ .

$r - 8 > - 8 \cdot 2$

Simplify the right side.

Multiply $- 8$ by $2$ .

$r - 8 > - 16$

Move all terms not containing $r$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$r > - 16 + 8$

Add $- 16$ and $8$ .

$r > - 8$

The result can be shown in multiple forms.

Inequality Form:

$r > - 8$

Interval Notation:

$(- 8, \infty)$