Solve the Inequality for s 2s+3>15

$2 s + 3 > 15$

Move all terms not containing $s$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$2 s > 15 - 3$

Subtract $3$ from $15$ .

$2 s > 12$

Divide each term in $2 s > 12$ by $2$ and simplify.

Divide each term in $2 s > 12$ by $2$ .

$\frac{2 s}{2} > \frac{12}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 s}{2} > \frac{12}{2}$

Divide $s$ by $1$ .

$s > \frac{12}{2}$

Simplify the right side.

Divide $12$ by $2$ .

$s > 6$

The result can be shown in multiple forms.

Inequality Form:

$s > 6$

Interval Notation:

$(6, \infty)$