Solve the Inequality for s 7s+8>=3s-1

$7 s + 8 \geq 3 s - 1$

Move all terms containing $s$ to the left side of the inequality.

Subtract $3 s$ from both sides of the inequality.

$7 s + 8 - 3 s \geq - 1$

Subtract $3 s$ from $7 s$ .

$4 s + 8 \geq - 1$

Move all terms not containing $s$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$4 s \geq - 1 - 8$

Subtract $8$ from $- 1$ .

$4 s \geq - 9$

Divide each term in $4 s \geq - 9$ by $4$ and simplify.

Divide each term in $4 s \geq - 9$ by $4$ .

$\frac{4 s}{4} \geq \frac{- 9}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 s}{4} \geq \frac{- 9}{4}$

Divide $s$ by $1$ .

$s \geq \frac{- 9}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$s \geq - \frac{9}{4}$

The result can be shown in multiple forms.

Inequality Form:

$s \geq - \frac{9}{4}$

Interval Notation:

$[- \frac{9}{4}, \infty)$