Solve the Inequality for s 8s+3<9s+1

$8 s + 3 < 9 s + 1$

Step 1

Move all terms containing $s$ to the left side of the inequality.

Subtract $9 s$ from both sides of the inequality.

$8 s + 3 - 9 s < 1$

Subtract $9 s$ from $8 s$ .

$- s + 3 < 1$

Step 2

Move all terms not containing $s$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$- s < 1 - 3$

Subtract $3$ from $1$ .

$- s < - 2$

Step 3

Divide each term in $- s < - 2$ by $- 1$ and simplify.

Divide each term in $- s < - 2$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- s}{- 1} > \frac{- 2}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{s}{1} > \frac{- 2}{- 1}$

Divide $s$ by $1$ .

$s > \frac{- 2}{- 1}$

Simplify the right side.

Divide $- 2$ by $- 1$ .

$s > 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$s > 2$

Interval Notation:

$(2, \infty)$

Solve the Inequality for s 8s+3<9s+1

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