Solve the Inequality for t 39<3t+3

$39 < 3 t + 3$

Rewrite so $t$ is on the left side of the inequality.

$3 t + 3 > 39$

Move all terms not containing $t$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$3 t > 39 - 3$

Subtract $3$ from $39$ .

$3 t > 36$

Divide each term in $3 t > 36$ by $3$ and simplify.

Divide each term in $3 t > 36$ by $3$ .

$\frac{3 t}{3} > \frac{36}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 t}{3} > \frac{36}{3}$

Divide $t$ by $1$ .

$t > \frac{36}{3}$

Simplify the right side.

Divide $36$ by $3$ .

$t > 12$

The result can be shown in multiple forms.

Inequality Form:

$t > 12$

Interval Notation:

$(12, \infty)$