Solve the Inequality for v 17v>=51

$17 v \geq 51$

Divide each term in $17 v \geq 51$ by $17$ .

$\frac{17 v}{17} \geq \frac{51}{17}$

Simplify the left side.

Cancel the common factor of $17$ .

Cancel the common factor.

$\frac{17 v}{17} \geq \frac{51}{17}$

Divide $v$ by $1$ .

$v \geq \frac{51}{17}$

$v \geq \frac{51}{17}$

$v \geq \frac{51}{17}$

Simplify the right side.

Divide $51$ by $17$ .

$v \geq 3$

$v \geq 3$

The result can be shown in multiple forms.

Inequality Form:

$v \geq 3$

Interval Notation:

$[3, \infty)$

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