Solve the Inequality for w (w+3)/2<-8

$\frac{w + 3}{2} < - 8$

Step 1

Multiply both sides by $2$ .

$\frac{w + 3}{2} \cdot 2 < - 8 \cdot 2$

Step 2

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{w + 3}{2} \cdot 2 < - 8 \cdot 2$

Rewrite the expression.

$w + 3 < - 8 \cdot 2$

Simplify the right side.

Multiply $- 8$ by $2$ .

$w + 3 < - 16$

Step 3

Move all terms not containing $w$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$w < - 16 - 3$

Subtract $3$ from $- 16$ .

$w < - 19$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$w < - 19$

Interval Notation:

$(- \infty, - 19)$