Solve the Inequality for x 10<3x+19

$10 < 3 x + 19$

Rewrite so $x$ is on the left side of the inequality.

$3 x + 19 > 10$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $19$ from both sides of the inequality.

$3 x > 10 - 19$

Subtract $19$ from $10$ .

$3 x > - 9$

Divide each term in $3 x > - 9$ by $3$ and simplify.

Divide each term in $3 x > - 9$ by $3$ .

$\frac{3 x}{3} > \frac{- 9}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} > \frac{- 9}{3}$

Divide $x$ by $1$ .

$x > \frac{- 9}{3}$

Simplify the right side.

Divide $- 9$ by $3$ .

$x > - 3$

The result can be shown in multiple forms.

Inequality Form:

$x > - 3$

Interval Notation:

$(- 3, \infty)$