Solve the Inequality for x 10>=x/2+8

$10 \geq \frac{x}{2} + 8$

Rewrite so $x$ is on the left side of the inequality.

$\frac{x}{2} + 8 \leq 10$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$\frac{x}{2} \leq 10 - 8$

Subtract $8$ from $10$ .

$\frac{x}{2} \leq 2$

Multiply both sides by $2$ .

$\frac{x}{2} \cdot 2 \leq 2 \cdot 2$

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{x}{2} \cdot 2 \leq 2 \cdot 2$

Rewrite the expression.

$x \leq 2 \cdot 2$

Simplify the right side.

Multiply $2$ by $2$ .

$x \leq 4$

The result can be shown in multiple forms.

Inequality Form:

$x \leq 4$

Interval Notation:

$(- \infty, 4]$