Solve the Inequality for x 10>=x-3

$10 \geq x - 3$

Rewrite so $x$ is on the left side of the inequality.

$x - 3 \leq 10$

Move all terms not containing $x$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$x \leq 10 + 3$

Add $10$ and $3$ .

$x \leq 13$

The result can be shown in multiple forms.

Inequality Form:

$x \leq 13$

Interval Notation:

$(- \infty, 13]$