Solve the Inequality for x 2(2x+1)>=10

$2 (2 x + 1) \geq 10$

Divide each term in $2 (2 x + 1) \geq 10$ by $2$ and simplify.

Divide each term in $2 (2 x + 1) \geq 10$ by $2$ .

$\frac{2 (2 x + 1)}{2} \geq \frac{10}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (2 x + 1)}{2} \geq \frac{10}{2}$

Divide $2 x + 1$ by $1$ .

$2 x + 1 \geq \frac{10}{2}$

Simplify the right side.

Divide $10$ by $2$ .

$2 x + 1 \geq 5$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$2 x \geq 5 - 1$

Subtract $1$ from $5$ .

$2 x \geq 4$

Divide each term in $2 x \geq 4$ by $2$ and simplify.

Divide each term in $2 x \geq 4$ by $2$ .

$\frac{2 x}{2} \geq \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} \geq \frac{4}{2}$

Divide $x$ by $1$ .

$x \geq \frac{4}{2}$

Simplify the right side.

Divide $4$ by $2$ .

$x \geq 2$

The result can be shown in multiple forms.

Inequality Form:

$x \geq 2$

Interval Notation:

$[2, \infty)$