Solve the Inequality for X -2(3X+2)>=-6X-4

$- 2 (3 X + 2) \geq - 6 X - 4$

Simplify $- 2 (3 X + 2)$ .

Rewrite.

$0 + 0 - 2 (3 X + 2) \geq - 6 X - 4$

Simplify by adding zeros.

$- 2 (3 X + 2) \geq - 6 X - 4$

Apply the distributive property.

$- 2 (3 X) - 2 \cdot 2 \geq - 6 X - 4$

Multiply.

Multiply $3$ by $- 2$ .

$- 6 X - 2 \cdot 2 \geq - 6 X - 4$

Multiply $- 2$ by $2$ .

$- 6 X - 4 \geq - 6 X - 4$

Move all terms containing $X$ to the left side of the inequality.

Add $6 X$ to both sides of the inequality.

$- 6 X - 4 + 6 X \geq - 4$

Combine the opposite terms in $- 6 X - 4 + 6 X$ .

Add $- 6 X$ and $6 X$ .

$0 - 4 \geq - 4$

Subtract $4$ from $0$ .

$- 4 \geq - 4$

Since $- 4 = - 4$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$