Solve the Inequality for x -2(8-3x)>=6x+2

$- 2 (8 - 3 x) \geq 6 x + 2$

Step 1

Simplify $- 2 (8 - 3 x)$ .

Rewrite.

$0 + 0 - 2 (8 - 3 x) \geq 6 x + 2$

Simplify by adding zeros.

$- 2 (8 - 3 x) \geq 6 x + 2$

Apply the distributive property.

$- 2 \cdot 8 - 2 (- 3 x) \geq 6 x + 2$

Multiply.

Multiply $- 2$ by $8$ .

$- 16 - 2 (- 3 x) \geq 6 x + 2$

Multiply $- 3$ by $- 2$ .

$- 16 + 6 x \geq 6 x + 2$

Step 2

Move all terms containing $x$ to the left side of the inequality.

Subtract $6 x$ from both sides of the inequality.

$- 16 + 6 x - 6 x \geq 2$

Combine the opposite terms in $- 16 + 6 x - 6 x$ .

Subtract $6 x$ from $6 x$ .

$- 16 + 0 \geq 2$

Add $- 16$ and $0$ .

$- 16 \geq 2$

Step 3

Since $- 16 \neq 2$ , there are no solutions.

No solution