Solve the Inequality for x 2^(x-1)>32

$2^{x - 1} > 32$

Create equivalent expressions in the equation that all have equal bases.

$2^{x - 1} > 2^{5}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x - 1 > 5$

Move all terms not containing $x$ to the right side of the inequality.

Add $1$ to both sides of the inequality.

$x > 5 + 1$

Add $5$ and $1$ .

$x > 6$

The result can be shown in multiple forms.

Inequality Form:

$x > 6$

Interval Notation:

$(6, \infty)$