Solve the Inequality for x -2(x+2)>=10

$- 2 (x + 2) \geq 10$

Step 1

Divide each term in $- 2 (x + 2) \geq 10$ by $- 2$ and simplify.

Divide each term in $- 2 (x + 2) \geq 10$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 (x + 2)}{- 2} \leq \frac{10}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 (x + 2)}{- 2} \leq \frac{10}{- 2}$

Divide $x + 2$ by $1$ .

$x + 2 \leq \frac{10}{- 2}$

Simplify the right side.

Divide $10$ by $- 2$ .

$x + 2 \leq - 5$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$x \leq - 5 - 2$

Subtract $2$ from $- 5$ .

$x \leq - 7$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 7$

Interval Notation:

$(- \infty, - 7]$

Solve the Inequality for x -2(x+2)>=10

Related Questions

Support LCMGCF.com by disabling your adblocker.