Solve the Inequality for x 21<=3+9x

$21 \leq 3 + 9 x$

Rewrite so $x$ is on the left side of the inequality.

$3 + 9 x \geq 21$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$9 x \geq 21 - 3$

Subtract $3$ from $21$ .

$9 x \geq 18$

Divide each term in $9 x \geq 18$ by $9$ and simplify.

Divide each term in $9 x \geq 18$ by $9$ .

$\frac{9 x}{9} \geq \frac{18}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} \geq \frac{18}{9}$

Divide $x$ by $1$ .

$x \geq \frac{18}{9}$

Simplify the right side.

Divide $18$ by $9$ .

$x \geq 2$

The result can be shown in multiple forms.

Inequality Form:

$x \geq 2$

Interval Notation:

$[2, \infty)$