Solve the Inequality for x 24<4x-3+5x+6

$24 < 4 x - 3 + 5 x + 6$

Rewrite so $x$ is on the left side of the inequality.

$4 x - 3 + 5 x + 6 > 24$

Simplify $4 x - 3 + 5 x + 6$ .

Add $4 x$ and $5 x$ .

$9 x - 3 + 6 > 24$

Add $- 3$ and $6$ .

$9 x + 3 > 24$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$9 x > 24 - 3$

Subtract $3$ from $24$ .

$9 x > 21$

Divide each term in $9 x > 21$ by $9$ and simplify.

Divide each term in $9 x > 21$ by $9$ .

$\frac{9 x}{9} > \frac{21}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} > \frac{21}{9}$

Divide $x$ by $1$ .

$x > \frac{21}{9}$

Simplify the right side.

Cancel the common factor of $21$ and $9$ .

Factor $3$ out of $21$ .

$x > \frac{3 (7)}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$x > \frac{3 \cdot 7}{3 \cdot 3}$

Cancel the common factor.

$x > \frac{3 \cdot 7}{3 \cdot 3}$

Rewrite the expression.

$x > \frac{7}{3}$

The result can be shown in multiple forms.

Inequality Form:

$x > \frac{7}{3}$

Interval Notation:

$(\frac{7}{3}, \infty)$