Solve the Inequality for x |2x-1|>3

$| 2 x - 1 | > 3$

Write $| 2 x - 1 | > 3$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$2 x - 1 \geq 0$

Solve the inequality.

Add $1$ to both sides of the inequality.

$2 x \geq 1$

Divide each term in $2 x \geq 1$ by $2$ and simplify.

Divide each term in $2 x \geq 1$ by $2$ .

$\frac{2 x}{2} \geq \frac{1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} \geq \frac{1}{2}$

Divide $x$ by $1$ .

$x \geq \frac{1}{2}$

In the piece where $2 x - 1$ is non-negative, remove the absolute value.

$2 x - 1 > 3$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$2 x - 1 < 0$

Solve the inequality.

Add $1$ to both sides of the inequality.

$2 x < 1$

Divide each term in $2 x < 1$ by $2$ and simplify.

Divide each term in $2 x < 1$ by $2$ .

$\frac{2 x}{2} < \frac{1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} < \frac{1}{2}$

Divide $x$ by $1$ .

$x < \frac{1}{2}$

In the piece where $2 x - 1$ is negative, remove the absolute value and multiply by $- 1$ .

$- (2 x - 1) > 3$

Write as a piecewise.

${\begin{cases} 2 x - 1 > 3 & x \geq \frac{1}{2} \\ - (2 x - 1) > 3 & x < \frac{1}{2} \end{cases}$

Simplify $- (2 x - 1) > 3$ .

Apply the distributive property.

${\begin{cases} 2 x - 1 > 3 & x \geq \frac{1}{2} \\ - (2 x) - - 1 > 3 & x < \frac{1}{2} \end{cases}$

Multiply $2$ by $- 1$ .

${\begin{cases} 2 x - 1 > 3 & x \geq \frac{1}{2} \\ - 2 x - - 1 > 3 & x < \frac{1}{2} \end{cases}$

Multiply $- 1$ by $- 1$ .

${\begin{cases} 2 x - 1 > 3 & x \geq \frac{1}{2} \\ - 2 x + 1 > 3 & x < \frac{1}{2} \end{cases}$

Solve $2 x - 1 > 3$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Add $1$ to both sides of the inequality.

$2 x > 3 + 1$

Add $3$ and $1$ .

$2 x > 4$

Divide each term in $2 x > 4$ by $2$ and simplify.

Divide each term in $2 x > 4$ by $2$ .

$\frac{2 x}{2} > \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} > \frac{4}{2}$

Divide $x$ by $1$ .

$x > \frac{4}{2}$

Simplify the right side.

Divide $4$ by $2$ .

$x > 2$

Solve $- 2 x + 1 > 3$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$- 2 x > 3 - 1$

Subtract $1$ from $3$ .

$- 2 x > 2$

Divide each term in $- 2 x > 2$ by $- 2$ and simplify.

Divide each term in $- 2 x > 2$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} < \frac{2}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} < \frac{2}{- 2}$

Divide $x$ by $1$ .

$x < \frac{2}{- 2}$

Simplify the right side.

Divide $2$ by $- 2$ .

$x < - 1$

Find the union of the solutions.

$x < - 1$ or $x > 2$

The result can be shown in multiple forms.

Inequality Form:

$x < - 1 or x > 2$

Interval Notation:

$(- \infty, - 1) \cup (2, \infty)$

Solve the Inequality for x |2x-1|>3

Related Questions

Support LCMGCF.com by disabling your adblocker.