Solve the Inequality for x -2x+3+x>-x-1

$- 2 x + 3 + x > - x - 1$

Add $- 2 x$ and $x$ .

$- x + 3 > - x - 1$

Move all terms containing $x$ to the left side of the inequality.

Add $x$ to both sides of the inequality.

$- x + 3 + x > - 1$

Combine the opposite terms in $- x + 3 + x$ .

Add $- x$ and $x$ .

$0 + 3 > - 1$

Add $0$ and $3$ .

$3 > - 1$

Since $3 > - 1$ , the inequality will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$