Solve the Inequality for x 2x+3y<=6

$2 x + 3 y \leq 6$

Step 1

Subtract $3 y$ from both sides of the inequality.

$2 x \leq 6 - 3 y$

Step 2

Divide each term in $2 x \leq 6 - 3 y$ by $2$ and simplify.

Divide each term in $2 x \leq 6 - 3 y$ by $2$ .

$\frac{2 x}{2} \leq \frac{6}{2} + \frac{- 3 y}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} \leq \frac{6}{2} + \frac{- 3 y}{2}$

Divide $x$ by $1$ .

$x \leq \frac{6}{2} + \frac{- 3 y}{2}$

Simplify the right side.

Simplify each term.

Divide $6$ by $2$ .

$x \leq 3 + \frac{- 3 y}{2}$

Move the negative in front of the fraction.

$x \leq 3 - \frac{3 y}{2}$