Solve the Inequality for x 3(-3+7x)<=-93

$3 (- 3 + 7 x) \leq - 93$

Divide each term in $3 (- 3 + 7 x) \leq - 93$ by $3$ and simplify.

Divide each term in $3 (- 3 + 7 x) \leq - 93$ by $3$ .

$\frac{3 (- 3 + 7 x)}{3} \leq \frac{- 93}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (- 3 + 7 x)}{3} \leq \frac{- 93}{3}$

Divide $- 3 + 7 x$ by $1$ .

$- 3 + 7 x \leq \frac{- 93}{3}$

Simplify the right side.

Divide $- 93$ by $3$ .

$- 3 + 7 x \leq - 31$

Move all terms not containing $x$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$7 x \leq - 31 + 3$

Add $- 31$ and $3$ .

$7 x \leq - 28$

Divide each term in $7 x \leq - 28$ by $7$ and simplify.

Divide each term in $7 x \leq - 28$ by $7$ .

$\frac{7 x}{7} \leq \frac{- 28}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} \leq \frac{- 28}{7}$

Divide $x$ by $1$ .

$x \leq \frac{- 28}{7}$

Simplify the right side.

Divide $- 28$ by $7$ .

$x \leq - 4$

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 4$

Interval Notation:

$(- \infty, - 4]$