Solve the Inequality for x 3+4x<=2(1+2x)

$3 + 4 x \leq 2 (1 + 2 x)$

Simplify $2 (1 + 2 x)$ .

Rewrite.

$3 + 4 x \leq 0 + 0 + 2 (1 + 2 x)$

Simplify by adding zeros.

$3 + 4 x \leq 2 (1 + 2 x)$

Apply the distributive property.

$3 + 4 x \leq 2 \cdot 1 + 2 (2 x)$

Multiply.

Multiply $2$ by $1$ .

$3 + 4 x \leq 2 + 2 (2 x)$

Multiply $2$ by $2$ .

$3 + 4 x \leq 2 + 4 x$

Move all terms containing $x$ to the left side of the inequality.

Subtract $4 x$ from both sides of the inequality.

$3 + 4 x - 4 x \leq 2$

Combine the opposite terms in $3 + 4 x - 4 x$ .

Subtract $4 x$ from $4 x$ .

$3 + 0 \leq 2$

Add $3$ and $0$ .

$3 \leq 2$

Since $3 \neq 2$ , there are no solutions.

No solution