Solve the Inequality for x -3/8x-2<-13+17

$- \frac{3}{8} x - 2 < - 13 + 17$

Simplify each term.

Combine $x$ and $\frac{3}{8}$ .

$- \frac{x \cdot 3}{8} - 2 < - 13 + 17$

Move $3$ to the left of $x$ .

$- \frac{3 x}{8} - 2 < - 13 + 17$

Add $- 13$ and $17$ .

$- \frac{3 x}{8} - 2 < 4$

Move all terms not containing $x$ to the right side of the inequality.

Add $2$ to both sides of the inequality.

$- \frac{3 x}{8} < 4 + 2$

Add $4$ and $2$ .

$- \frac{3 x}{8} < 6$

Divide each term in $- \frac{3 x}{8} < 6$ by $- 1$ and simplify.

Divide each term in $- \frac{3 x}{8} < 6$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- \frac{3 x}{8}}{- 1} > \frac{6}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{\frac{3 x}{8}}{1} > \frac{6}{- 1}$

Divide $\frac{3 x}{8}$ by $1$ .

$\frac{3 x}{8} > \frac{6}{- 1}$

Simplify the right side.

Divide $6$ by $- 1$ .

$\frac{3 x}{8} > - 6$

Multiply both sides by $8$ .

$\frac{3 x}{8} \cdot 8 > - 6 \cdot 8$

Simplify.

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{3 x}{8} \cdot 8 > - 6 \cdot 8$

Rewrite the expression.

$3 x > - 6 \cdot 8$

Simplify the right side.

Multiply $- 6$ by $8$ .

$3 x > - 48$

Divide each term in $3 x > - 48$ by $3$ and simplify.

Divide each term in $3 x > - 48$ by $3$ .

$\frac{3 x}{3} > \frac{- 48}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} > \frac{- 48}{3}$

Divide $x$ by $1$ .

$x > \frac{- 48}{3}$

Simplify the right side.

Divide $- 48$ by $3$ .

$x > - 16$

The result can be shown in multiple forms.

Inequality Form:

$x > - 16$

Interval Notation:

$(- 16, \infty)$

Solve the Inequality for x -3/8x-2<-13+17

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