Solve the Inequality for x -3(9+x)>=-21

$- 3 (9 + x) \geq - 21$

Step 1

Divide each term in $- 3 (9 + x) \geq - 21$ by $- 3$ and simplify.

Divide each term in $- 3 (9 + x) \geq - 21$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 (9 + x)}{- 3} \leq \frac{- 21}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (9 + x)}{- 3} \leq \frac{- 21}{- 3}$

Divide $9 + x$ by $1$ .

$9 + x \leq \frac{- 21}{- 3}$

Simplify the right side.

Divide $- 21$ by $- 3$ .

$9 + x \leq 7$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $9$ from both sides of the inequality.

$x \leq 7 - 9$

Subtract $9$ from $7$ .

$x \leq - 2$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 2$

Interval Notation:

$(- \infty, - 2]$

Solve the Inequality for x -3(9+x)>=-21

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