Solve the Inequality for x 3^(x+2)<27

$3^{x + 2} < 27$

Step 1

Create equivalent expressions in the equation that all have equal bases.

$3^{x + 2} < 3^{3}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 2 < 3$

Step 3

Move all terms not containing $x$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$x < 3 - 2$

Subtract $2$ from $3$ .

$x < 1$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x < 1$

Interval Notation:

$(- \infty, 1)$

Step 5