Solve the Inequality for x 3(x-3)<=3

$3 (x - 3) \leq 3$

Step 1

Divide each term in $3 (x - 3) \leq 3$ by $3$ and simplify.

Divide each term in $3 (x - 3) \leq 3$ by $3$ .

$\frac{3 (x - 3)}{3} \leq \frac{3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (x - 3)}{3} \leq \frac{3}{3}$

Divide $x - 3$ by $1$ .

$x - 3 \leq \frac{3}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$x - 3 \leq 1$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$x \leq 1 + 3$

Add $1$ and $3$ .

$x \leq 4$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x \leq 4$

Interval Notation:

$(- \infty, 4]$