Solve the Inequality for x 3x>=-12

$3 x \geq - 12$

Divide each term in $3 x \geq - 12$ by $3$ .

$\frac{3 x}{3} \geq \frac{- 12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} \geq \frac{- 12}{3}$

Divide $x$ by $1$ .

$x \geq \frac{- 12}{3}$

$x \geq \frac{- 12}{3}$

$x \geq \frac{- 12}{3}$

Simplify the right side.

Divide $- 12$ by $3$ .

$x \geq - 4$

$x \geq - 4$

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 4$

Interval Notation:

$[- 4, \infty)$

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