Solve the Inequality for x -3x-3<=6

$- 3 x - 3 \leq 6$

Move all terms not containing $x$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$- 3 x \leq 6 + 3$

Add $6$ and $3$ .

$- 3 x \leq 9$

Divide each term in $- 3 x \leq 9$ by $- 3$ and simplify.

Divide each term in $- 3 x \leq 9$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 x}{- 3} \geq \frac{9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} \geq \frac{9}{- 3}$

Divide $x$ by $1$ .

$x \geq \frac{9}{- 3}$

Simplify the right side.

Divide $9$ by $- 3$ .

$x \geq - 3$

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 3$

Interval Notation:

$[- 3, \infty)$

Solve the Inequality for x -3x-3<=6

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