Solve the Inequality for x 42+10x<=3x

$42 + 10 x \leq 3 x$

Move all terms containing $x$ to the left side of the inequality.

Subtract $3 x$ from both sides of the inequality.

$42 + 10 x - 3 x \leq 0$

Subtract $3 x$ from $10 x$ .

$42 + 7 x \leq 0$

Subtract $42$ from both sides of the inequality.

$7 x \leq - 42$

Divide each term in $7 x \leq - 42$ by $7$ and simplify.

Divide each term in $7 x \leq - 42$ by $7$ .

$\frac{7 x}{7} \leq \frac{- 42}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} \leq \frac{- 42}{7}$

Divide $x$ by $1$ .

$x \leq \frac{- 42}{7}$

Simplify the right side.

Divide $- 42$ by $7$ .

$x \leq - 6$

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 6$

Interval Notation:

$(- \infty, - 6]$