Solve the Inequality for x 4x+2<3x-4

$4 x + 2 < 3 x - 4$

Move all terms containing $x$ to the left side of the inequality.

Subtract $3 x$ from both sides of the inequality.

$4 x + 2 - 3 x < - 4$

Subtract $3 x$ from $4 x$ .

$x + 2 < - 4$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$x < - 4 - 2$

Subtract $2$ from $- 4$ .

$x < - 6$

The result can be shown in multiple forms.

Inequality Form:

$x < - 6$

Interval Notation:

$(- \infty, - 6)$