Solve the Inequality for x 4x+3<x-3

$4 x + 3 < x - 3$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $x$ from both sides of the inequality.

$4 x + 3 - x < - 3$

Subtract $x$ from $4 x$ .

$3 x + 3 < - 3$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$3 x < - 3 - 3$

Subtract $3$ from $- 3$ .

$3 x < - 6$

Step 3

Divide each term in $3 x < - 6$ by $3$ and simplify.

Divide each term in $3 x < - 6$ by $3$ .

$\frac{3 x}{3} < \frac{- 6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} < \frac{- 6}{3}$

Divide $x$ by $1$ .

$x < \frac{- 6}{3}$

Simplify the right side.

Divide $- 6$ by $3$ .

$x < - 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x < - 2$

Interval Notation:

$(- \infty, - 2)$