Solve the Inequality for x 54x+64>=49x+59

$54 x + 64 \geq 49 x + 59$

Move all terms containing $x$ to the left side of the inequality.

Subtract $49 x$ from both sides of the inequality.

$54 x + 64 - 49 x \geq 59$

Subtract $49 x$ from $54 x$ .

$5 x + 64 \geq 59$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $64$ from both sides of the inequality.

$5 x \geq 59 - 64$

Subtract $64$ from $59$ .

$5 x \geq - 5$

Divide each term in $5 x \geq - 5$ by $5$ and simplify.

Divide each term in $5 x \geq - 5$ by $5$ .

$\frac{5 x}{5} \geq \frac{- 5}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} \geq \frac{- 5}{5}$

Divide $x$ by $1$ .

$x \geq \frac{- 5}{5}$

Simplify the right side.

Divide $- 5$ by $5$ .

$x \geq - 1$

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 1$

Interval Notation:

$[- 1, \infty)$