Solve the Inequality for x 58-10x<=20+9x

$58 - 10 x \leq 20 + 9 x$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $9 x$ from both sides of the inequality.

$58 - 10 x - 9 x \leq 20$

Subtract $9 x$ from $- 10 x$ .

$58 - 19 x \leq 20$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $58$ from both sides of the inequality.

$- 19 x \leq 20 - 58$

Subtract $58$ from $20$ .

$- 19 x \leq - 38$

Step 3

Divide each term in $- 19 x \leq - 38$ by $- 19$ and simplify.

Divide each term in $- 19 x \leq - 38$ by $- 19$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 19 x}{- 19} \geq \frac{- 38}{- 19}$

Simplify the left side.

Cancel the common factor of $- 19$ .

Cancel the common factor.

$\frac{- 19 x}{- 19} \geq \frac{- 38}{- 19}$

Divide $x$ by $1$ .

$x \geq \frac{- 38}{- 19}$

Simplify the right side.

Divide $- 38$ by $- 19$ .

$x \geq 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \geq 2$

Interval Notation:

$[2, \infty)$

Solve the Inequality for x 58-10x<=20+9x

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