Solve the Inequality for x 5x+5(x-9)<10x-9

$5 x + 5 (x - 9) < 10 x - 9$

Simplify $5 x + 5 (x - 9)$ .

Simplify each term.

Apply the distributive property.

$5 x + 5 x + 5 \cdot - 9 < 10 x - 9$

Multiply $5$ by $- 9$ .

$5 x + 5 x - 45 < 10 x - 9$

Add $5 x$ and $5 x$ .

$10 x - 45 < 10 x - 9$

Move all terms containing $x$ to the left side of the inequality.

Subtract $10 x$ from both sides of the inequality.

$10 x - 45 - 10 x < - 9$

Combine the opposite terms in $10 x - 45 - 10 x$ .

Subtract $10 x$ from $10 x$ .

$0 - 45 < - 9$

Subtract $45$ from $0$ .

$- 45 < - 9$

Since $- 45 < - 9$ , the inequality will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$