Solve the Inequality for x 6(2x-1)>=3(4x+1)

$6 (2 x - 1) \geq 3 (4 x + 1)$

Step 1

Simplify $6 (2 x - 1)$ .

Start simplifying.

$0 + 0 + 6 (2 x - 1) \geq 3 (4 x + 1)$

Simplify by adding zeros.

$6 (2 x - 1) \geq 3 (4 x + 1)$

Apply the distributive property.

$6 (2 x) + 6 \cdot - 1 \geq 3 (4 x + 1)$

Multiply.

Multiply $2$ by $6$ .

$12 x + 6 \cdot - 1 \geq 3 (4 x + 1)$

Multiply $6$ by $- 1$ .

$12 x - 6 \geq 3 (4 x + 1)$

Step 2

Simplify $3 (4 x + 1)$ .

Apply the distributive property.

$12 x - 6 \geq 3 (4 x) + 3 \cdot 1$

Multiply.

Multiply $4$ by $3$ .

$12 x - 6 \geq 12 x + 3 \cdot 1$

Multiply $3$ by $1$ .

$12 x - 6 \geq 12 x + 3$

Step 3

Move all terms containing $x$ to the left side of the inequality.

Subtract $12 x$ from both sides of the inequality.

$12 x - 6 - 12 x \geq 3$

Combine the opposite terms in $12 x - 6 - 12 x$ .

Subtract $12 x$ from $12 x$ .

$0 - 6 \geq 3$

Subtract $6$ from $0$ .

$- 6 \geq 3$

Step 4

Since $- 6 \neq 3$ , there are no solutions.

No solution