Solve the Inequality for x -8(x-1)-x<=-28

$- 8 (x - 1) - x \leq - 28$

Simplify $- 8 (x - 1) - x$ .

Simplify each term.

Apply the distributive property.

$- 8 x - 8 \cdot - 1 - x \leq - 28$

Multiply $- 8$ by $- 1$ .

$- 8 x + 8 - x \leq - 28$

Subtract $x$ from $- 8 x$ .

$- 9 x + 8 \leq - 28$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$- 9 x \leq - 28 - 8$

Subtract $8$ from $- 28$ .

$- 9 x \leq - 36$

Divide each term in $- 9 x \leq - 36$ by $- 9$ and simplify.

Divide each term in $- 9 x \leq - 36$ by $- 9$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 9 x}{- 9} \geq \frac{- 36}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 x}{- 9} \geq \frac{- 36}{- 9}$

Divide $x$ by $1$ .

$x \geq \frac{- 36}{- 9}$

Simplify the right side.

Divide $- 36$ by $- 9$ .

$x \geq 4$

The result can be shown in multiple forms.

Inequality Form:

$x \geq 4$

Interval Notation:

$[4, \infty)$

Solve the Inequality for x -8(x-1)-x<=-28

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