Solve the Inequality for x 8(x-3)>4(2x-6)

$8 (x - 3) > 4 (2 x - 6)$

Step 1

Simplify $8 (x - 3)$ .

Start simplifying.

$0 + 0 + 8 (x - 3) > 4 (2 x - 6)$

Simplify by adding zeros.

$8 (x - 3) > 4 (2 x - 6)$

Apply the distributive property.

$8 x + 8 \cdot - 3 > 4 (2 x - 6)$

Multiply $8$ by $- 3$ .

$8 x - 24 > 4 (2 x - 6)$

Step 2

Simplify $4 (2 x - 6)$ .

Apply the distributive property.

$8 x - 24 > 4 (2 x) + 4 \cdot - 6$

Multiply.

Multiply $2$ by $4$ .

$8 x - 24 > 8 x + 4 \cdot - 6$

Multiply $4$ by $- 6$ .

$8 x - 24 > 8 x - 24$

Step 3

Move all terms containing $x$ to the left side of the inequality.

Subtract $8 x$ from both sides of the inequality.

$8 x - 24 - 8 x > - 24$

Combine the opposite terms in $8 x - 24 - 8 x$ .

Subtract $8 x$ from $8 x$ .

$0 - 24 > - 24$

Subtract $24$ from $0$ .

$- 24 > - 24$

Step 4

Since $- 24 < - 24$ , there are no solutions.

No solution