Solve the Inequality for x 8x-2>=-18

$8 x - 2 \geq - 18$

Move all terms not containing $x$ to the right side of the inequality.

Add $2$ to both sides of the inequality.

$8 x \geq - 18 + 2$

Add $- 18$ and $2$ .

$8 x \geq - 16$

Divide each term in $8 x \geq - 16$ by $8$ and simplify.

Divide each term in $8 x \geq - 16$ by $8$ .

$\frac{8 x}{8} \geq \frac{- 16}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} \geq \frac{- 16}{8}$

Divide $x$ by $1$ .

$x \geq \frac{- 16}{8}$

Simplify the right side.

Divide $- 16$ by $8$ .

$x \geq - 2$

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 2$

Interval Notation:

$[- 2, \infty)$