Solve the Inequality for x 8x>=-32

$8 x \geq - 32$

Step 1

Divide each term in $8 x \geq - 32$ by $8$ .

$\frac{8 x}{8} \geq \frac{- 32}{8}$

Step 2

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} \geq \frac{- 32}{8}$

Divide $x$ by $1$ .

$x \geq \frac{- 32}{8}$

$x \geq \frac{- 32}{8}$

$x \geq \frac{- 32}{8}$

Step 3

Simplify the right side.

Divide $- 32$ by $8$ .

$x \geq - 4$

$x \geq - 4$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 4$

Interval Notation:

$[- 4, \infty)$

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