Solve the Inequality for x 8x-5x-4<=-3+3x

$8 x - 5 x - 4 \leq - 3 + 3 x$

Subtract $5 x$ from $8 x$ .

$3 x - 4 \leq - 3 + 3 x$

Move all terms containing $x$ to the left side of the inequality.

Subtract $3 x$ from both sides of the inequality.

$3 x - 4 - 3 x \leq - 3$

Combine the opposite terms in $3 x - 4 - 3 x$ .

Subtract $3 x$ from $3 x$ .

$0 - 4 \leq - 3$

Subtract $4$ from $0$ .

$- 4 \leq - 3$

Since $- 4 \leq - 3$ , the inequality will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$