Solve the Inequality for x 8x-8<=-72

$8 x - 8 \leq - 72$

Step 1

Move all terms not containing $x$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$8 x \leq - 72 + 8$

Add $- 72$ and $8$ .

$8 x \leq - 64$

Step 2

Divide each term in $8 x \leq - 64$ by $8$ and simplify.

Divide each term in $8 x \leq - 64$ by $8$ .

$\frac{8 x}{8} \leq \frac{- 64}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} \leq \frac{- 64}{8}$

Divide $x$ by $1$ .

$x \leq \frac{- 64}{8}$

Simplify the right side.

Divide $- 64$ by $8$ .

$x \leq - 8$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 8$

Interval Notation:

$(- \infty, - 8]$