Solve the Inequality for x 9x-8>4x+7

$9 x - 8 > 4 x + 7$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $4 x$ from both sides of the inequality.

$9 x - 8 - 4 x > 7$

Subtract $4 x$ from $9 x$ .

$5 x - 8 > 7$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$5 x > 7 + 8$

Add $7$ and $8$ .

$5 x > 15$

Step 3

Divide each term in $5 x > 15$ by $5$ and simplify.

Divide each term in $5 x > 15$ by $5$ .

$\frac{5 x}{5} > \frac{15}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} > \frac{15}{5}$

Divide $x$ by $1$ .

$x > \frac{15}{5}$

Simplify the right side.

Divide $15$ by $5$ .

$x > 3$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x > 3$

Interval Notation:

$(3, \infty)$