Solve the Inequality for x by-d<=ax+c

$b y - d \leq a x + c$

Step 1

Rewrite so $x$ is on the left side of the inequality.

$a x + c \geq b y - d$

Step 2

Subtract $c$ from both sides of the inequality.

$a x \geq b y - d - c$

Step 3

Divide each term in $a x \geq b y - d - c$ by $a$ and simplify.

Divide each term in $a x \geq b y - d - c$ by $a$ .

$\frac{a x}{a} \geq \frac{b y}{a} + \frac{- d}{a} + \frac{- c}{a}$

Simplify the left side.

Cancel the common factor of $a$ .

Cancel the common factor.

$\frac{a x}{a} \geq \frac{b y}{a} + \frac{- d}{a} + \frac{- c}{a}$

Divide $x$ by $1$ .

$x \geq \frac{b y}{a} + \frac{- d}{a} + \frac{- c}{a}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$x \geq \frac{b y}{a} - \frac{d}{a} + \frac{- c}{a}$

Move the negative in front of the fraction.

$x \geq \frac{b y}{a} - \frac{d}{a} - \frac{c}{a}$