Solve the Inequality for x (x+1)(x-2)<=0

$(x + 1) (x - 2) \leq 0$

Step 1

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x - 2 = 0$

Step 2

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 3

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Step 4

The final solution is all the values that make $(x + 1) (x - 2) \leq 0$ true.

$x = - 1, 2$

Step 5

Use each root to create test intervals.

$x < - 1$

$- 1 < x < 2$

$x > 2$

Step 6

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

Test a value on the interval $x < - 1$ to see if it makes the inequality true.

Choose a value on the interval $x < - 1$ and see if this value makes the original inequality true.

$x = - 4$

Replace $x$ with $- 4$ in the original inequality.

$((- 4) + 1) ((- 4) - 2) \leq 0$

The left side $18$ is greater than the right side $0$ , which means that the given statement is false.

False

Test a value on the interval $- 1 < x < 2$ to see if it makes the inequality true.

Choose a value on the interval $- 1 < x < 2$ and see if this value makes the original inequality true.

$x = 0$

Replace $x$ with $0$ in the original inequality.

$((0) + 1) ((0) - 2) \leq 0$

The left side $- 2$ is less than the right side $0$ , which means that the given statement is always true.

True

Test a value on the interval $x > 2$ to see if it makes the inequality true.

Choose a value on the interval $x > 2$ and see if this value makes the original inequality true.

$x = 4$

Replace $x$ with $4$ in the original inequality.

$((4) + 1) ((4) - 2) \leq 0$

The left side $10$ is greater than the right side $0$ , which means that the given statement is false.

False

Compare the intervals to determine which ones satisfy the original inequality.

$x < - 1$ False

$- 1 < x < 2$ True

$x > 2$ False

$x < - 1$ False

$- 1 < x < 2$ True

$x > 2$ False

Step 7

The solution consists of all of the true intervals.

$- 1 \leq x \leq 2$

Step 8

The result can be shown in multiple forms.

Inequality Form:

$- 1 \leq x \leq 2$

Interval Notation:

$[- 1, 2]$

Step 9

Solve the Inequality for x (x+1)(x-2)<=0

Related Questions

Support LCMGCF.com by disabling your adblocker.